607=9r^2-5

Solution for 607=9r^2-5 equation:

607=9r^2-5

We move all terms to the left:

607-(9r^2-5)=0

We get rid of parentheses

-9r^2+5+607=0

We add all the numbers together, and all the variables

-9r^2+612=0

a = -9; b = 0; c = +612;
Δ = b2-4ac
Δ = 02-4·(-9)·612
Δ = 22032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22032}=\sqrt{1296*17}=\sqrt{1296}*\sqrt{17}=36\sqrt{17}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{17}}{2*-9}=\frac{0-36\sqrt{17}}{-18}
=-\frac{36\sqrt{17}}{-18}
=-\frac{2\sqrt{17}}{-1}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{17}}{2*-9}=\frac{0+36\sqrt{17}}{-18}
=\frac{36\sqrt{17}}{-18}
=\frac{2\sqrt{17}}{-1}
$